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12. Class 12th Physics | Terrestrial Magnetism | Solved Example-1 on Both Magnetism

6 Comments



in this example we are given that a bar magnet
is zero point 1 meter long and its pole strength is 12 amp-ere meter. and here we are required
to find the magnetic induction at a point on its axis at a distance of zero point 2
meter from its centre. now in this situation if we. draw the picture. or we can see if
this is bar magnet. which is having length zero point 1 meter. and in this situation.
its. centre, is located at a distance of zero point 2 meter. from the point where we are
required to calculate the magnetic induction, we named this point say as p. now in this
situation if we consider this as r. and say, this is the north pole of magnet and this
is the south pole. then we know that due to north pole at point p the magnetic induction
will exist away from it and due to south pole it’ll exist toward it. so here we can write
that. net magnetic induction at point p. can be given as b-p is equal to, b-n minus b-s,
because north pole is closer to point p, so the magnetic induction due to it will be more.
and due to a magnetic pole. the magnetic induction is given as k m by the distance square so
due to the north pole. if we consider the pole strength to be m, as in a magnet the
2. poles have identical pole strength which we can denote by plus and minus or m-n and
m-s. here due to north pole we can directly write this is given as mu-not upon 4 pie.
m divided by the distance square if this distance is taken as l. then we can write it l minus
l by 2. so it is r minus l by 2 whole square. minus due to. the south pole it’ll be mu-not
upon 4 pie. m divided by the distance will b r plus l by 2 whole square. if we simplify
the result finally we are getting here mu-not m, over 4 pie we can take common. and if we
square these terms and we take l-c-m in numerator we’ll getting, this will be r-l plus r-l
it’ll be. 2 r-l divided by. r square minus l square by 4 whole square. and in this situation.
the final result if we simplify. then finally we’ll be getting here, if we just simplify
the result and substitute the numerical values you can see here. this 4 square 16 can be
taken in numerator so this will be. 32 mu-not m, r l. divided by 4 pie. 4 r square minus
l square. whole square. we substitute the values this magnetic field at point p will
be give by 32 mu-not upon 4 pie we can write as 10 to power minus 7. multiplied by. the
product of m and l, which is the dipole moment of this magnet which is already given at 12
amp-ere per meter we can take it 12. multiplied by, here. you can consider the value. of.
r to be zero point 2 meter. then divided by. if we substitute the values of r square and
l square over here. here we are getting it 4 multiplied by zero point 2 whole square
minus zero point 1 whole square. whole square. and if we simplify the expression directly
i can write down the final result which we’ll get is 3 point 4 into 10 to power minus 4
tesla. that will be the answer to this problem.

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6 thoughts on “12. Class 12th Physics | Terrestrial Magnetism | Solved Example-1 on Both Magnetism”

  1. Sanjukta M says:

    Sir do you suggest watching advanced illustrations right after the basic videos or on completion of all the basic lectures, it could be like a revision of concepts?

  2. alpa Desai says:

    sir why did you not took value of L in numerator where u put the values instead of variables??

  3. Abhishek Thaker says:

    sir if i am not wrong, in the question we are given pole strength, m=12 Am and not M=ml=12 Am.please answer..

  4. jeeten jain says:

    The correct answer must be 3.4*10^(-5)

  5. Prashant Darshan says:

    goodmorning sir
    sir i have watched all 3 caps of jee mains 2019 i have got print of all online papers from 2014
    offline i have from 2003 that arihant one
    sir my query is should i watch adv illustration now or leave like u said we should converge our studies now thanking u for ur great guidance by ur video lectures i have improved my performance to a great extend earlier three months back i failed in school exams in maths and chem by ur videos i completed phy within 1 month with great concept clearity so i got relief from one sub then i did my maths from gtewani even HOD of allen vadodara jitesh sir was great help now few chapters of organic are remaining that i did from prince sir lectures that are on utube of etoos institute i go to fiitjee but our teachers focus more on top batch more so i didnt go from july onwards and wasted august but then by sept i watched ur videos i came back on track i took admsn in allen vadodara only coz of u my rank and marks improved alot in major test now leader test series will start i will do well thats im pretty sure about it and all credit goes to u in future i will surely come to meet u in jaipur
    Thank u sir

  6. Kaushik Burugupally says:

    Sir why can’t we use 2km/r^3?

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