in this example figure shows. two small bar
magnets placed at separation r. and we are required to find the magnetic interaction
energy of this system of dipoles. so here we are treating. the 2 magnets as dipole because
these are very small bar magnets. so on solution the very first thing here we can treat that,
the separation between the poles if this d. then d is very-very less then r because these
are treated as dipoles and these are very small bar magnets. now if we wish to find
out the magnetic. induction due to first dipole at the location of second, so we can write
magnetic induction at. location of, m-2. due to m-1 ,is. obviously as this m-2 is located
on the axial point of m-1 directly we can write magnetic induction is b-1 which is the
radial magnetic field. and it can be give as 2 k m-1 by r cube. which can be written
as mu-not upon 4 pie this 2 gets cancelled out so it is mu not m-1. by 2 pie r cube this
is the magnetic induction due to m-1 at the location of m-2 and it’ll be in radial direction
this b-1 vector. here i can write because. the. sheet is going out of visual. so in this
situation this is b-1 vector it exist in the direction along, radial direction of m-1.
now if we calculate the interaction energy. of, m-2 in the field of. m-1. then here you
can see. the interaction energy can be given as u is equal to minus m-2. dot, b-1. b-1
is a field due to m-1 at the location of m-2. so in this situation it can be given as minus,
m-2 b-1 coz theta. if we substitute the values we are getting it minus. mu-not m-1 m-2 by,
2 pie, r cube coz theta. that will be the answer to this problem.

Shouldnt the magnetic interaction energy be the sum of (U of M1 on M2 and U of M2 on M1) .If no , then why ?? .And when we will canculate B of M2 the , we will have to take two components i guess ? One along the axis of M2 and another along its perpendicular bisector ??

sir where is the formula of interaction energy i mean which video lectures please send me the link or explain me how did the formula come from thanks in advance

Shouldnt the magnetic interaction energy be the sum of (U of M1 on M2 and U of M2 on M1) .If no , then why ?? .And when we will canculate B of M2 the , we will have to take two components i guess ? One along the axis of M2 and another along its perpendicular bisector ??

sir where is the formula of interaction energy i mean which video lectures please send me the link or explain me how did the formula come from thanks in advance

Sir how u wrote the relation (u=B1.M2)

sir why will be the interection energy same for both