wonderfully explained…but we can do this in a different way as the magnitude of both the charges r the same…so we can put the mathmatical formula of electric dipole… E=K.p/r^3;p=dipole moment=q*d&r=4m as given…we can use this formula when the point in at the vertical area from the middle point of both charges…then theta=90 the general formula is E=K*p/r^3*(1+3cos^2theta)

This is wonderful thank you! Reviewing the trig steps as you went a long was really helpful.

Wow! you are awesome! you are so thorough !

Such a good explanation. Thank you

you just too good man. I appreciate this

Nice, but honestly could have just multiplied Ex with the ratio 3/5 instead of doing the whole trig thing.

This was a really thorough and detailed explanation that leads to learning

This is beautiful

This video was amazing. The small but ubiquitous edits were a great addition to the silky smooth drawing and writing of the work.

BRUTAL! Thanks!!

wonderfully explained…but we can do this in a different way as the magnitude of both the charges r the same…so we can put the mathmatical formula of electric dipole…

E=K.p/r^3;p=dipole moment=q*d&r=4m as given…we can use this formula when the point in at the vertical area from the middle point of both charges…then theta=90

the general formula is E=K*p/r^3*(1+3cos^2theta)

Wish my damn professor would have taught me like this 🙁

Could you consider this a dipole?

Slow down you understands it but I don’t 🙃

I kinds wish there was an example of 3 or more charges but besides that, a fantastic explanation

Excellent.

I wish this guy spoke a little more slowly and smoothly, like Sal does. This guy hurts my brain like a woodpecker.